# Difference between revisions of "Hosed"

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James has approximately 20 minutes till he experiences mental meltdown for the evening | James has approximately 20 minutes till he experiences mental meltdown for the evening | ||

--><math>(t = .3)</math> | --><math>(t = .3)</math> | ||

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+ | Example 2: | ||

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+ | The Goodazzle frosh spent $2 hrs$ this morning designing today's [[Pikachu of the Day]]. Then they decided to take [[Pikachu]] for a stroll through the [[Infinite Corridor]] in his [[Pikamobile]]. Since the [[Pikamobile]] travels at $.001 \frac{smoots}{minute}$ and the [[Infinite Corridor]] is approximately $\infty smoots$ long, this stroll lasted about $t = \frac{\infty smoots}{.001 \frac{smoots}{minute}} = 2 hrs$. Then they spent $4 hrs$ wandering around the roofs, for Frigga-knows-what-reason, and then spent $1.5 hrs$ looking for a text-to-speech generator that would sing the Magical Pika song. Because of this heavy frosh workload, they barely had time to play Super Smash Bros. and certainly didn't have time to draw random pictures on the [[Goodale]] whiteboard, like they did yesterday. Poor frosh. | ||

Thus: | Thus: |

## Revision as of 03:01, 30 September 2005

Hosed: (adj) When a certain quantity of work is required by the institvte, with a disproportionately less quantity of time to do it in.

<math>H=\frac{P\cdot W}{t}</math>

H=hosedness, P=Punting (distractions/hour), W=Work Assigned - Work Ignored (assignments), t=time(hours)

Example:

James has 6 unified problems due tomorrow, an n-question physics take-home quiz on thurdsay, and a 10 question relativity p-set due friday. He also has 2 physics p-sets from previous weeks to catch up on, (but will probably punt them so they are subtracted out) --><math>(W = 16+n)</math>

James went hiking all weekend, in New York, and is currently writing an entry for the wiki. --><math>(P = 30d/h)</math>

James has approximately 20 minutes till he experiences mental meltdown for the evening --><math>(t = .3)</math>

Example 2:

The Goodazzle frosh spent $2 hrs$ this morning designing today's Pikachu of the Day. Then they decided to take Pikachu for a stroll through the Infinite Corridor in his Pikamobile. Since the Pikamobile travels at $.001 \frac{smoots}{minute}$ and the Infinite Corridor is approximately $\infty smoots$ long, this stroll lasted about $t = \frac{\infty smoots}{.001 \frac{smoots}{minute}} = 2 hrs$. Then they spent $4 hrs$ wandering around the roofs, for Frigga-knows-what-reason, and then spent $1.5 hrs$ looking for a text-to-speech generator that would sing the Magical Pika song. Because of this heavy frosh workload, they barely had time to play Super Smash Bros. and certainly didn't have time to draw random pictures on the Goodale whiteboard, like they did yesterday. Poor frosh.

Thus: --><math>H = (30d/h)*(16+n)/(.3)</math> = about usual.

The Institute tries to control hosedness and the negative affects it often has on MIT students by giving "Student Holidays" every month. This time is often used relaxing, sleeping, and doing things freshmen do all year long thanks to pass/no record.